72 lines
1.5 KiB
Bash
72 lines
1.5 KiB
Bash
set -u
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set -e
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# ParseArgs will parse a string that contains quoted strings the same as bash does
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# (same as most other *nix shells do). This is secure in the sense that it doesn't do any
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# executing or interpeting. However, it also doesn't do any escaping, so you shouldn't pass
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# these strings to shells without escaping them.
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parseargs() {
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notquote="-"
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str=$1
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declare -a m=()
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s=""
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# Strip leading space, then trailing space, then add a terminating space.
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str="${str## }"
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str="${str%% }"
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str+=" "
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last_quote="${notquote}"
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is_space=""
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n=$(( ${#str} - 1 ))
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i=-1
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for ((i=0;i<=$n;i+=1)); do
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c="${str:$i:1}"
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# If we're ending a quote, break out and skip this character
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if [ "$c" == "$last_quote" ]; then
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last_quote=$notquote
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continue
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fi
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# If we're in a quote, count this character
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if [ "$last_quote" != "$notquote" ]; then
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s+=$c
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continue
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fi
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# If we encounter a quote, enter it and skip this character
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if [ "$c" == "'" ] || [ "$c" == '"' ]; then
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is_space=""
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last_quote=$c
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continue
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fi
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# If it's a space, store the string
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re="[[:space:]]+" # must be used as a var, not a literal
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if [[ $c =~ $re ]]; then
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if [ "0" == "$i" ] || [ -n "$is_space" ]; then
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echo continue $i $is_space
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continue
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fi
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is_space="true"
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m+=("$s")
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s=""
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continue
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fi
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is_space=""
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s+="$c"
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done
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if [ "$last_quote" != "$notquote" ]; then
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>&2 echo "error"
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return 1
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fi
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for arg in "${m[@]}"; do
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echo "$arg"
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done
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return 0
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}
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