better param parsing #36

coolaj86 · 2019-05-28T23:09:55Z

coolaj86 코멘트됨,

2019-05-28 23:09:55 +00:00

소유자

Removing any and all of the following leading characters before parsing the params: #/?.

#access_token=x&foo=bar => access_token=x&foo=bar
#/?access_token=x&foo=bar => access_token=x&foo=bar
#/access_token=x&foo=bar => access_token=x&foo=bar
#?access_token=x&foo=bar => access_token=x&foo=bar

Removing any and all of the following leading characters before parsing the params: `#/?`. * `#access_token=x&foo=bar` => `access_token=x&foo=bar` * `#/?access_token=x&foo=bar` => `access_token=x&foo=bar` * `#/access_token=x&foo=bar` => `access_token=x&foo=bar` * `#?access_token=x&foo=bar` => `access_token=x&foo=bar`

Ghost 이 변경사항을 승인하였습니다. 2019-05-29 01:49:48 +00:00

lib/html/js/app.js

						
				@ -4,3 +4,3 @@

				document.body.hidden = false;

				var hash = window.location.hash.substr(1);

				var hash = window.location.hash.replace(/^[\/#?]+/, '');