Fun stuff.

Codecademy.md

@@ -322,6 +322,39 @@ else:
   print(more_than_n([2, 4, 6, 2, 3, 2, 1, 2], 2, 3))
 ```
 
+## More frequency analysis
+```
+def more_frequent_item(lst, item1, item2):
+  if (lst.count(item1)) > (lst.count(item2)):
+    return item1
+  if lst.count(item2) > lst.count(item1):
+    return item2
+  if lst.count(item1) == lst.count(item2):
+    return item1
+
+#Uncomment the line below when your function is done
+print(more_frequent_item([2, 3, 3, 2, 3, 2, 3, 2, 3], 2, 3))
+```
+
+## A creative original solution to grabbing the middle of an index (solving their problem with their names)
+
+```
+def middle_element(lst):
+if len(lst) % 2 > 0:
+  rounded = round(len(lst) / 2)
+  rounded = int(rounded)
+  print(rounded)
+  return lst[rounded]
+
+elif len(lst) % 2 == 0:
+ position = int((len(lst) / 2) - 1)
+ position2 = int(len(lst) / 2)
+ both = (lst[position] + lst[position2]) / 2
+ return both
+
+print(middle_element([5, 2, -10, -4, 4, 5, 7]))
+```
+
 ### Sublists
 
 Grab a subset of a list using `sublist = letters[1:6]` This would give you index **1-5**.