From b0d9c1542c3b243233fedc9323dda75fdc4775b5 Mon Sep 17 00:00:00 2001
From: Josh Mudge <josh@cityofardon.com>
Date: Sat, 22 Sep 2018 20:40:39 -0600
Subject: [PATCH] Add frequency function.

---
 caeser-cipher.py | 31 ++++++++++++++++++-------------
 ex7-dots.py      | 29 +++++++++++++++++++++++++++++
 2 files changed, 47 insertions(+), 13 deletions(-)
 create mode 100644 ex7-dots.py

diff --git a/caeser-cipher.py b/caeser-cipher.py
index 1f69055..eee6f1b 100644
--- a/caeser-cipher.py
+++ b/caeser-cipher.py
@@ -1,38 +1,43 @@
 import re # Import Regex tools
 import string # Import string tools
+import collections
+
 ciphertext = input("Please type in your cipher text:") # Set variable cipertext to the input from user.
+shiftNum = input("Please enter the shift used:") # Get input
 ciphertext = re.sub (r'([^a-zA-Z ]+?)', '', ciphertext) # Remove all non-letters.
-ciphertext = ciphertext.lower() # Make it all lowercase.
+ciphertext = ciphertext.lower() # Make it all lowercase. https://www.geeksforgeeks.org/isupper-islower-lower-upper-python-applications/
 letters = list(string.ascii_lowercase) # Use a list of lowercase letters. https://stackoverflow.com/questions/43918437/how-to-iterate-through-the-alphabet
 letterCount = 0 # Set variable for keeping track of which letter in the ciphertext we're on.
 letterPos = 0 # Set variable for keeping track of the letter's position in the alphabet.
 answer = "" # The solution.
-shiftNum = input("Please enter the shift used:") # Get input
 
 for c in ciphertext: # For every letter in the ciphertext
     #Upletters = list(string.ascii_uppercase)
-    while letterPos < 26: # While the letter's position in the alphabet is less than
+    while letterPos < 26: # While the letter's position in the alphabet is less than 26 (and thus valid), continue.
         if ciphertext[letterCount] == letters[letterPos]: # Match the letter in the ciphertext to a letter in the alphabet and once they match, continue.
-            letter = int(letterPos) + int(shiftNum) # Take the position of the letter and the shift number.  NOTE: catch spaces.
-            if letter > 25:
+            letter = int(letterPos) + int(shiftNum) # Take the position of the letter and the shift number and add them for the enciphered letter.
+            if letter > 25: # If the enciphered letter's position is not valid because it is too high, fix it by rotating around the alphabet.
                 letter = letter - 26
             if letter < 0:
-                letter = letter + 26
-            answer = answer + letters[letter]
+                letter = letter + 26 # If the enciphered letter's position is not valid because it is too low, fix it by rotating around the alphabet.
+            answer = answer + letters[letter] # Add letters together to get the enciphered text.
 
-        letterPos = letterPos + 1
-    if letterPos > 25:
+        letterPos = letterPos + 1 # Iterate through letter positions in the alphabet. (neccessary to find one that matches.)
+
+    if letterPos > 25: # If the letter position
         letterPos = letterPos - 26
 
     letterCount = letterCount + 1
 
-print("\nYour enciphered text is: " + answer)
 
-#alphabet = '"abcd","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"' #old alphabet string for an array in JS
-#print(re.sub (r'([^a-zA-Z]+?)', '', alphabet)) # strip everything except letters
+def freq():
+    print(collections.Counter(answer).most_common()[0][0]) # Find most common letter https://stackoverflow.com/questions/47251934/how-to-count-the-most-frequent-letter-in-a-string
+
+print("\nYour enciphered text is: " + answer) #  NOTE TO SELF: catch spaces for nice formatting in answer.
+freq()
 
 '''
-On line #4
+On line #4 Regex
 This feeds a regex to re.sub literally "If it doesn't match letters or spaces, convert it to nothing, process this variable."
 Scrub extranous info or typos.
 r marks it as a string literal (no escaping needed)
diff --git a/ex7-dots.py b/ex7-dots.py
new file mode 100644
index 0000000..6afb845
--- /dev/null
+++ b/ex7-dots.py
@@ -0,0 +1,29 @@
+print("Mary had a little lamb.") # Print string
+print("Its fleece was white as {}.".format('snow')) # Print string with format.
+print("And everywhere that Mary went.") # Print string.
+
+with open('out.txt', 'w') as f:
+    print("." * 1000000000, file=f)  # A little fun with a billion dots being saved to a file.
+
+end1 = "C" # Set variable to a string.
+end2 = "h" # Set variable to a string.
+end3 = "e" # Set variable to a string.
+end4 = "e" # Set variable to a string.
+end5 = "s" # Set variable to a string.
+end6 = "e" # Set variable to a string.
+end7 = "B" # Set variable to a string.
+end8 = "u" # Set variable to a string.
+end9 = "r" # Set variable to a string.
+end10 = "g" # Set variable to a string.
+end11 = "e" # Set variable to a string.
+end12 = "r" # Set variable to a string.
+
+
+# watch end = ' ' at the end. try removing it to see what happens.
+print(end1 + end2 + end3 + end4 + end5 + end6, end=' ') # Print combined variables without a space in between on the same line as the next set of them with a space in between:
+print(end7 + end8 + end9 + end10 + end11 + end12) # Print variables without spaces in between
+
+#1. Done
+#2. Done
+
+# Break it.